# A car ravels along a straight road to the east for 100 meters in 4 seconds

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✅Question :

A car ravels along a straight road to the east for 100 meters in 4 seconds, then to the west for 50meters in 1 second. Determine (i) Average speed (2 mks) (ii) Average velocity

(i) Average Speed:

Average speed is calculated by dividing the total distance traveled by the total time taken. In this case, the car traveled 100 meters to the east and then 50 meters to the west.

Total distance = 100 meters (east) + 50 meters (west) = 150 meters Total time = 4 seconds (east) + 1 second (west) = 5 seconds

Average speed = Total distance / Total time Average speed = 150 meters / 5 seconds Average speed = 30 meters/second

(ii) Average Velocity:

Average velocity takes into account both the distance traveled and the direction. Since the car traveled east and then west, the average velocity will consider the displacement (change in position) as well.

Displacement = Final position – Initial position

The car traveled 100 meters east and then 50 meters west. The net displacement can be calculated as:

Displacement = 100 meters (east) – 50 meters (west) = 50 meters east

Total time = 4 seconds (east) + 1 second (west) = 5 seconds

Average velocity = Displacement / Total time Average velocity = 50 meters / 5 seconds Average velocity = 10 meters/second east

So, the answers are: (i) Average speed = 30 meters/second (ii) Average velocity = 10 meters/second east

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